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[" 13."|[1/a,1,bc],[1/b,1,ca],[1/c,1,ab]...

[" 13."|[1/a,1,bc],[1/b,1,ca],[1/c,1,ab]|=],[[" (A) "0," (B) "abc],[" (C) "(1)/(abc)," (D) कोई नही "]]

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|[1,a,bc] , [1,b,ca] , [1,c,ab]|=

(1)/(a),1,bc(1)/(b),1,ca(1)/(c),1,ab]|=0

Evaluate: |[1,a,bc],[1,b,ca],[1,c,ab]|

Delta = |(1//a,1,bc),(1//b,1,ca),(1//c,1,ab)|=

Delta = |(1//a,1,bc),(1//b,1,ca),(1//c,1,ab)|=

|[1,a, bc] ,[1, b, ca], [1, c, ab]| = (a-b)(b-c)(c-a)

|[1,bc,a(b+c)],[1,ca,b(c+a)],[1,ab,c(a+b)]|=0

Without expanding show that |[1/a,1,bc],[1/b,1,ca],[1/c,1,ab]|=0

Prove [[(1)/(a),1,bc(1)/(b),1,ca(1)/(c),1,ab]]=0

|[1,1,1],[a,b,c],[bc,ca,ab]|=(a-b)(b-c)(c-a)