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[1+sec20^(@)=],[" 1) "tan40^(@)tan30^(@)...

[1+sec20^(@)=],[" 1) "tan40^(@)tan30^(@)]

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tan20^(@)tan40^(@)tan80^(@)

tan20^(@)tan30^(@)tan40^(@)tan80^(@)=1

tan 70^(@) - tan 20^(@) -2 tan 40^(@)=

tan 70^(@) - tan 20^(@) -2 tan 40^(@)=

tan20^(@)tan40^(@)tan60^(@)tan80^(@)

tan10^(@) tan 20^(@) tan 30^(@) tan 40^(@) tan 50^(@) tan 60^(@) tan 70^(@) tan 80^(@)=

Find tan 20^(@) + tan40^(@) + sqrt(3)tan20^(@)tan40^(@) .

The value of tan 40^(@) + tan 20^(@) + sqrt(3) tan 20^(@) tan 40^(@) is equal to

The value of tan 40^(@) + tan 20^(@) + sqrt(3) tan 20^(@) tan 40^(@) is

Prove that: tan20^(@)tan30^(@)tan40^(@)tan80^(@)=1