|x-3|+2|x+1|=4

|(x-3)|+2|(x+1)|=4

if |(x+1,x-1),(x-3,x+2)|= |(4,-1),(1,3)|. find the value of x.

Lt_(x to oo)((8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1))=

underset(x to 1//2)lim {(8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1)}=

lim_ (x rarr (1) / (2)) ((8x-3) / (2x-1) - (4x ^ (2) +1) / (4x ^ (2) -1))

lim_(x to 1/2)((8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1)) .

Check whether the following are quadratic equations : (1) (x-2)^(2)+1=2x-3 (2) x(x+1)=8=(x+2)(x-2) (3) x(2x+3)=x^(2)+1 (4) (x+2)^(3) = x^(3)-4

If |(x+1,x-1),(x-3,x+2)|=|(4,-1),(1,3)| , then write the value of x .

If |(x+1,x-1),(x-3,x+2)|=|(4,-1),(1,3)| , then write the value of x .