A moving electron has `4.55 xx 10^(-25)` joules of kinetic energy. Calculate its wavelength (mass` = 9.1 xx 10^(-31)` kg and `h = 6.626 xx 10^(-34) kg m^2 s^(-1)` ).
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Here we given kinetic energy `1/2 mv^2 = 4.55 xx 10^(-25) J` `m = 9.1 xx 10^(-31) kg ` `h = 6.626 xx 10^(-34) kg m^2 s^(-1)` ` therefore 1/2 xx (9.1 xx 10^(-31) ) v^2 = 4.55 xx 10^(-25)` ` v^2 = (4.55 xx 10^(-25) xx 2)/(9.1 xx 10^(-31)) = 10^6` ` v = 10^3 ms^(-1)` ` therefore lamda = (h)/(mv) = (6.626 xx 10^(-34))/((9.1 xx 10^(-31) ) xx 10^3)` ` = 7.25 xx 10^(-7) m`
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