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For a compound K(4)[Fe(CN)6] to 4K^(+) +...

For a compound `K_(4)[Fe(CN)_6] to 4K^(+) + [Fe(CN)_6]^(4-)`, the complex ion is

A

`K^(+)`

B

`CN^(-)`

C

`Fe^(II)`

D

`[Fe(CN)_6]^(4-)`

Text Solution

Verified by Experts

The correct Answer is:
`[Fe(CN)_6]^(4-)`
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