Home
Class 12
CHEMISTRY
On neutron bombardment fragmentation of ...

On neutron bombardment fragmentation of U-235 occurs according to the equation
`92^(U^(235)) + 0^(n^(1)) rarr 42^(Mo^(95)) + 57^(La^(139)) + x_(-1)^(e^(0)) + y_(0)^(n^(1))` Calculate the values of x and y.

Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    NCERT GUJARATI|Exercise SELF EVALUATION|23 Videos

  • NUCLEAR CHEMISTRY

    NCERT GUJARATI|Exercise SELF EVALUATION|23 Videos

  • ISOMERISM IN ORGANIC CHEMISTRY

    NCERT GUJARATI|Exercise SELF EVALUATION (CONFORMATION)|2 Videos

  • ORGANIC NITROGEN COMPOUNDS

    NCERT GUJARATI|Exercise Diazonium chloride|4 Videos

Similar Questions

Explore conceptually related problems

On neutron bombardment fragmentation of U-235 occurs according to the equation. 92^(U^(235)) + ^(0n^(1)) rarr 42^(Mo^(98)) + 54^(Xe^(136)) + x_(-1)^(e^(0)) + y 0^(n^(1)) Calculate the values of x and y.

If (2.3)^x = (0.23)^y = 1000 , then find the value of 1/x- 1/y

If sqrt(x^(2) + y^(2))=a. e^(tan^(-1)((y)/(x))), a gt 0 then the value of y''(0) is…….

Solution of the differential equation (1+e^(x/y))dx + e^(x/y)(1-x/y)dy=0 is

Find the equation of the normal to the curve y=(1+x)^(y)+sin^(-1)(sin^(2)x) at x = 0.

Find the equations of the tangent and normal to the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 at the point (x_(0), y_(0)) .

92^(U^(235)) nucleus absorbs a neutron and disintegrates into 54^(Xe^(139)), 38^(Sr^(94)) and x. What will be the product x?

Find the particular solution of the differential equation (1 + e^(2x))dy + (1 + y^(2))e^(x)dx = 0 , given that y = 1 when x = 0

If the following equations x+y-3 = 0, (1+lamda)x + (2+lamda) y - 8 = 0, x-(1+lamda)y + (2+lamda) = 0 are consistent then the value of lamda is