Home
Class 12
CHEMISTRY
On neutron bombardment fragmentation of ...

On neutron bombardment fragmentation of U-235 occurs according to the equation.
`92^(U^(235)) + ^(0n^(1)) rarr 42^(Mo^(98)) + 54^(Xe^(136)) + x_(-1)^(e^(0))` + y `0^(n^(1))` Calculate the values of x and y.

Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    NCERT GUJARATI|Exercise SELF EVALUATION|23 Videos
  • NUCLEAR CHEMISTRY

    NCERT GUJARATI|Exercise SELF EVALUATION|23 Videos
  • ISOMERISM IN ORGANIC CHEMISTRY

    NCERT GUJARATI|Exercise SELF EVALUATION (CONFORMATION)|2 Videos
  • ORGANIC NITROGEN COMPOUNDS

    NCERT GUJARATI|Exercise Diazonium chloride|4 Videos

Similar Questions

Explore conceptually related problems

On neutron bombardment fragmentation of U-235 occurs according to the equation 92^(U^(235)) + 0^(n^(1)) rarr 42^(Mo^(95)) + 57^(La^(139)) + x_(-1)^(e^(0)) + y_(0)^(n^(1)) Calculate the values of x and y.

If sqrt(x^(2) + y^(2))=a. e^(tan^(-1)((y)/(x))), a gt 0 then the value of y''(0) is…….

e^(x) tan y dx + (1 - e^(x))sec^(2)y dy = 0

If (2.3)^x = (0.23)^y = 1000 , then find the value of 1/x- 1/y

Find the equation of the normal to the curve y=(1+x)^(y)+sin^(-1)(sin^(2)x) at x = 0.

92^(U^(235)) nucleus absorbs a neutron and disintegrates into 54^(Xe^(139)), 38^(Sr^(94)) and x. What will be the product x?

Solution of the differential equation (1+e^(x/y))dx + e^(x/y)(1-x/y)dy=0 is

e^(x) + e^(y) = e^(x+ y) then prove that, (dy)/(dx) + (e^(x) (e^(y)-1))/(e^(y) (e^(x)-1))=0

If the following equations x+y-3 = 0, (1+lamda)x + (2+lamda) y - 8 = 0, x-(1+lamda)y + (2+lamda) = 0 are consistent then the value of lamda is