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If the equilibrium constants of followin...

If the equilibrium constants of following reactions are `2A hArr B` is `K_(1)` and `B hArr2A` is `K_(2)`, then

A

`K_(1)=2K_(2)`

B

`K_(1)=1//K_(2)`

C

`K_(2)=(K_(1))^(2)`

D

`K_(1)=1//K_(2)^(" "2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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