Home
Class 12
CHEMISTRY
Dissociation equilibrium constant of HI ...

Dissociation equilibrium constant of HI is `2.06xx10^(-2)` at `458^(@)C`. At equilibrium, concentrations of HI and `I_(2)` are `0.36M` and `0.15M` respectively. What is the equilibrium concentration of `H_(2)` at `458^(@)C`.

Text Solution

Verified by Experts

The correct Answer is:
`[H_(2)]=1.78xx10^(-2)M`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM - II

    NCERT GUJARATI|Exercise SELF EVALUATION (C. Answer not exceeding 60 words)|1 Videos

  • CARBOXYLIC ACIDS

    NCERT GUJARATI|Exercise SELF EVALUATION((B) Answer in one or two sentences :)|1 Videos

  • CHEMICAL KINETICS-II

    NCERT GUJARATI|Exercise SELF EVALUATION ((D) Solve the problems :)|7 Videos

Similar Questions

Explore conceptually related problems

For the equilibrium 2SO_(3(g))hArr2SO_(2(g))+O_(2(g)) , the value of equilibrium constant is 4.8xx10^(-3) at 700^(@)C . At equilibrium, if the concentration of SO_(3) and SO_(2) are 0.60M and 0.15M respectively. Calculate the concentration of O_(2) in the equillibrium mixture.

For the equilibrium reaction H_(2(g))+I_(2(g))hArr 2HI_((g))

If system is in equilibrium then find relation between m_(1) and m_(2)

Hydrogen iodide is injected into a container at 458^(@)C . Certain amount of HI dissociates to H_(2) and I_(2) At equilibrium, concentration of HI is found to be 0.421M while [H_(2)] and [I_(2)] each equal to 6.04xx10^(-2)M , at 458^(@)C . Calculate the value of the equilibrium constant of the dissociation of HI at the same temperature.

For the reaction A+BhArr3C at 25^(@)C , a 3 litre volume reaction vessel contains 1,2 and 4 moles of A,B and C respectively at equilibrium, calculate the equilibrium constant K_(c) of the reaction at 25^(@)C .