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The emf of the half cell Cu((aq))^(2+)//...

The emf of the half cell `Cu_((aq))^(2+)//Cu_((s))` containing `"0.01 M Cu"^(2+)` solution is `+0.301 V`. Calculate the standard emf of the half cell.

Text Solution

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`n-2, E_(Cu^(2+)//Cu)^(@)=0.359V`
Hint : `E_(Cu^(2+)//Cu)=E_(Cu^(2+)//Cu)^(@)-(0.0591)/(2)log""(1)/([Cu^(2+)])`
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