In the given figure, `AB||DC and AD||BC` show that `DeltaABC ~= Delta CDA`.

In the given figure, angle ADE = angle B (i) Show that Delta ABC ~ Delta ADE (ii) If AD = 3.8 cm, AE = 3.6cm, BE = 2.1 cm and BC = 4.2 cm, find DE.

In the given figure, AL || DC, E is mid point of BC. Show that DeltaEBL ~= DeltaECD .

In the given figure, if DeltaABE cong DeltaACD , show that DeltaADE ~ DeltaABC

In the given figure, AD is a median of a DeltaABC and AM bot BC . Prove that : AB^(2)= AD^(2)-BC*DM+((BC)/(2))^(2)

In the given figure, AD is a median of a DeltaABC and AM bot BC . Prove that : AC^(2)+AB^(2)= 2AD^(2)+(1)/(2) BC^(2)

In the given figure, AD is a median of a DeltaABC and AM bot BC . Prove that : AC^(2)= AD^(2)+BC*DM+((BC)/(2))^(2)

In the given figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that (ar(ABC))/(ar(DBC))= (AO)/(DO) .

In the given figures, OA = OB and OD = OC. Show that (i) triangleAOD = triangleBOC and (ii) AD||BC

Sides AB and BC and median AD of a DeltaABC are respectively proportional to sides PQ and QR and median PM of DeltaPQR (see the given figure). Show that DeltaABC ~ DeltaPQR .

In the given figure, AB and DC are both perpendicular to line segment AD. BC intersects AD at P and P is the midpoint of AD. Prove that, ( 1 ) AB = CD ( 2 ) P is the midpoint of BC.