In the adjacent figure `DeltaABC and DeltaDBC` are two triangles such that `bar(AB) = bar(BD)` and `bar(AC) = bar(CD)` . Show that `DeltaABC ~= DeltaDBC.`

In the figure, ΔABC and ΔABD are two triangles on the same base AB. If line segment CD is bisected by bar(AB) at O, show that ar (DeltaABC) = ar (DeltaABD).

In DeltaABC , the bisector of angleA is bar(AD) . bar(AD)=alpha bar(AB)+beta bar(AC) , where ……………..

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In the adjacent figure DeltaABC is isosceles as bar(AB) = bar(AC), bar(BA) and bar(CA) are produced to Q and P such that bar(AQ) = bar(AP) . . Show that bar(PB) = bar(QC) .

In the given figure, ABD is a Deltaright angled at A and AC bot BD . Show that AB^(2)= BC*BD

In the adjacent figure, AB = BC and AC = CD . Prove that : /_ BAD : /_ ADB = 3 : 1.

In the given figure, DeltaABC is a right angled Deltawith /_B= 90^(@) and BD is perpendicular to AC. Prove that DeltaADB ~ DeltaABC

In the given figure AB and CD bisect each other at O. Prove that AC = BD.

In the adjacent figure, we have AC = XD, C and D are mid points of AB and XY respectively. Show that AB = XY.

In the adjacent figure DeltaABC, D is the midpoint of BC. DE_|_AB, DF_|_AC and DE = DF . Show that DeltaBED ~= Delta CFD .