Home
Class 9
MATHS
In the figure PR and QS are two diameter...

In the figure PR and QS are two diameters. Is PQ = RS?

Text Solution

Verified by Experts

The correct Answer is:
Yes
Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    NCERT GUJARATI|Exercise EXERCISE 12.3|6 Videos
  • CIRCLES

    NCERT GUJARATI|Exercise EXERCISE 12.4|8 Videos
  • CIRCLES

    NCERT GUJARATI|Exercise EXERCISE 12.1|8 Videos
  • AREAS

    NCERT GUJARATI|Exercise EXERCISE 11.3|9 Videos
  • CO-ORDINATE GEOMETRY

    NCERT GUJARATI|Exercise Try These|2 Videos

Similar Questions

Explore conceptually related problems

In the given figure, AB and CD are two diameters of a circle (with centre O) perpendicular to each other and OD is the diameter of the smaller circle. If OA = 7 cm, find the area of the shaded region.

In the given figure, A, B and C are points on OP, OQ and OR respectively such that AB||PQ" and "AC||PR . Show that BC||QR .

In the given figure, PQ and RS are two mirrors placed parallel to each other. An incident ray AB strikes the mirror PQ at B, reflected ray moves along the path BC and strikes the mirror RS at C and again reflects back along CD. Prove that AB||CD

In the adjacent figure, A, B and C are points on OP, OQ and OR respectively such that AB || PQ and AC||PR. Show that BC || QR.

In the given figure, PQRS is a diameter of circle with radius 6cm, such that the lengths PQ, QR and RS are equal. Semicircles are drawn on PQ and QS as diameters. Find the area of the shaded region.

In the given figure, PR gt PQ and PS bisects angle QPR. Prove that angle PSR gt angle PSQ .

In the given figure, CM and RN are respectively the medians of DeltaABC and DeltaPQR . If DeltaABC ~DeltaPQR , prove that, (CM)/(RN)=(AB)/(PQ)

In the given figure, PS in the bisector of /_QPR " of "DeltaPQR . Prove that (QS)/(SR)= (PQ)/(PR) .

Find the area of the segments shaded in figure, if PQ=24cm, PR=7cm and QR is the diameter of the circle with centre O ( Take pi=(22)/(7))

In adjacent figure, PR > PQ and PS bisects /_QPR . Prove that /_PSR > /_PSQ .