Can you construct the triangle ABC with the same measures by changing the base angle `angleC` instead of `angleB` ? Draw a rough sketch and construct it

Can you draw the triangle with the same measurements in alternate way?

Can you construct a triangle ABC with BC = 6 cm, angleB=60^(@) and AB + AC = 5cm.? If not, give reasons.

Construct a circumcircle of the triangle ABC where AB = 5cm, angleB = 75^@ and BC = 7cm

ABC and DBC are two isosceles triangles on the same base BC (see the given figure). Show that angle ABD = angle ACD .

triangle ABC and triangle DBC are isosceles triangles on the same base BC. Prove that line AD bisects BC at right angles

triangle ABC and triangle DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see the given figure). If AD is extended to intersect BC at P, show that, ( i ) triangle ABD = triangle ACD (ii) triangle ABP = triangle ACP (iii) AP bisects angle A as well as angle D. (iv) AP is the perpendicular bisector of BC

Construct a triangle ABC, in which angleB =60^(@),angleC=45^(@) and AB + BC + CA = 11 cm.

Draw triangle ABC with BC = 4 cm, AC = 5 cm and angle C = 120^(@). Then construct a triangle whose side are 4/5 of the corresponding side of Delta ABC.

If an angle and a side of a right angle triangle is known , then rest of the sides and angles can be found as follows In DeltaABC (figure ), if angleB=90^(@),angleC=theta and BC=x , then AB=x tan theta and AC=x sec theta . Now, consider in isosceles triangle PQR (Figure 2), Where PQ=PR and 20N=sqrt(3) On the basis of the above information answer the question The angle of triangle PQR are

If an angle and a side of a right angle triangle is known , then rest of the sides and angles can be found as follows In DeltaABC (figure ), if angleB=90^(@),angleC=theta and BC=x , then AB=x tan theta and AC=x sec theta . Now, consider in isosceles triangle PQR (Figure 2), Where PQ=PR and 20N=sqrt(3) On the basis of the above information answer the question Length of the side QR is