Home
Class 10
MATHS
ABCD is a trapezium with AB||DC. E and F...

ABCD is a trapezium with `AB||DC`. E and F are points on non-parallel sides AD and BC respectively such that EF is parallel to AB (see the figure). Show that `(AE)/(ED)=(BF)/(FC)`

Text Solution

Verified by Experts

The correct Answer is:
`(AE)/(ED) = (BF)/(FC)`
Promotional Banner

Topper's Solved these Questions

  • SIMILAR TRIANGLES

    NCERT GUJARATI|Exercise DO THIS (FILL IN THE BLANKS)|6 Videos
  • SIMILAR TRIANGLES

    NCERT GUJARATI|Exercise DO THIS TRUE /FALSE|5 Videos
  • SETS

    NCERT GUJARATI|Exercise Try This|11 Videos
  • STATISTICS

    NCERT GUJARATI|Exercise THINK AND DISCUSS|8 Videos

Similar Questions

Explore conceptually related problems

ABCD is a trapezium with AB||DC . E and F are points on non-parallel sides Ad and BC respectively such that EF is parallel to AB (see the given figure). Show that (AE)/(ED)=(BF)/(FC) .

In DeltaABC , E and F are the midpoints of sides AB and AC respectively. If EF=5cm, find BC.

E and F are respec­tively the midpoints of equal sides AB and AC of triangle ABC (see the given figure). Show that BF = CE.

ABCD is quadrilateral E, F, G and H are the midpoints of AB, BC, CD and DA respectively. Prove that EFGH is a parallelogram.

P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD show that ar(DeltaAPB) = ar Delta(BQC)

In a parallelogram ABCD, E and F are the midpoints of the sides AB and DC respectively. Show that the line segments AF and EC trisect the diagonal BD.

D is a point on side BC ΔABC such that AD = AC (see figure). Show that AB > AD.

D is a point on side BC of triangle ABC such that AD = AC (see the given figure). Show that AB gt AD.

D and E are points on the sides CA and CB respectively of a DeltaABC right angled at C. Prove that AE^(2)+BD^(2)= AB^(2)+DE^(2) .

In the adjacent figure ABCD is a parallelogram P and Q are the midpoints of sides AB and DC respectively. Show that PBCQ is also a parallelogram.