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CD and GH are respectively the bisectors...

CD and GH are respectively the bisectors of `/_ACB" and "/_EGF` such that D and H lie on sides AB and FE of `DeltaABC" and "DeltaEFG` respectively. If `DeltaABC ~ DeltaFEG`, show that :
`(CD)/(GH)=(AC)/(FG)`

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