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A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is `60^(@)`. From another point 20m away from this point on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is `30^(@)` (see the given figure). Find the height of the tower and the width of the canal.

Answer

Step by step text solution for A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is 60^(@). From another point 20m away from this point on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is 30^(@) (see the given figure). Find the height of the tower and the width of the canal. by MATHS experts to help you in doubts & scoring excellent marks in Class 10 exams.

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A tower stands vertically on the ground. From a point on the ground, which is 15m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 60^(@) . Find the height of the tower.

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Knowledge Check

  • The angle of elevation of the top of a 15m high tower from a point 15m away from the base of the tower is………

    A
    `30^(@)`
    B
    `60^(@)`
    C
    `45^(@)`
    D
    `75^(@)`

  • The angle of elevation of the top of a tower from a point P on the ground is alpha . After walking a distance of d m towards the foot of the tower, the angle of elevation of the top of the tower is found to be beta . Then, ………..holds good.

    A
    `alpha lt beta`
    B
    `alpha gt beta`
    C
    `alpha = beta`
    D
    none of these

  • The angle of elevation of the top of a tower at a distance 500m from the foot is 30^(@) . Then, the height of the tower is ………m.

    A
    `250 sqrt3`
    B
    `500 sqrt3`
    C
    `(500)/(sqrt3)`
    D
    250

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