`3(x-1) le 2 (x-3)`

3x+4y le 12

Draw the graph of y=[x^(3)], when -2^(1//3)le x le 2^(1//3)

f(x)= {(|x+1|",",x lt -2),(2x+3",",-2 le x lt 0),(x^(2) + 3",",0 le x lt 3),(x^(3)-15,3 le x):} . Find at which points, the function f(x) is discontinuous ?

(3(x-2))/( 5) le (5(2-x))/(3)

5 (2x -7) -3 (2x+3) le 0, 2x+19 le 6x+47 .

f(x)= {(2x+3",","if" x le 2),(2x-3",","if" x gt 2):}

If f(x)={{:(,x[x], 0 le x lt 2),(,(x-1)[x], 2 le x lt 3):} where [.] denotes the greatest integer function, then (x) is continuous at x=2

The region formed by the inequalities 2x+3y-5 le 0, 4x-3y+2 le 0" and " x ge 0 ………