Evaluate (sqrt3 + sqrt2 )^6 - ( sqrt3...

Evaluate `(sqrt3 + sqrt2 )^6 - ( sqrt3 - sqrt2)^6` .

Verified by Experts

The correct Answer is:

396`sqrt6`

BINOMIAL THEOREM
NCERT GUJARATI|Exercise EXERCISE 8.2|12 Videos
APPENDIX 2 MATHEMATICAL MODELLING
NCERT GUJARATI|Exercise EXAMPLE|3 Videos
COMPLEX NUMBERS AND QUADRATIC EQUATIONS
NCERT GUJARATI|Exercise MISCELLANEOUS EXERCISES ON CHAPTER 24|1 Videos

Similar Questions

Explore conceptually related problems

Find (a +b)^4 - (a - b)^4 . Hence, evaluate (sqrt3 + sqrt2)^4 - (sqrt3 - sqrt2)^4 .

Evaluate : (sqrt(3)+sqrt(2))^(6)-(sqrt(3)-sqrt(2))^(6)

(sqrt3+ sqrt2) (sqrt3-sqrt2) =……

If p= (sqrt3- sqrt2) /( sqrt3+ sqrt2) and q= (sqrt3+sqrt2)/( sqrt3- sqrt2) , find the value of p^(2) +q^(2) .

Find (x + 1)^6 + (x-1)^6 . Hence or otherwise evaluate (sqrt2 + 1)^6 + (sqrt2 - 1)^6 .

Add 2sqrt2+5sqrt3 and sqrt2 - 3 sqrt3

4sqrt(6)xx3sqrt(24) = :-

Add 2sqrt2+5sqrt3 and sqrt2-3sqrt2

sqrt(3)x^(2) - sqrt(2)x + 3sqrt(3)=0

If 'a' and 'b' are rational numbers, find the value of a and b in each of the following equations. (sqrt3+sqrt2)/(sqrt3-sqrt2)=a+bsqrt6