Home
Class 11
MATHS
The mean and standard deviation of a gro...

The mean and standard deviation of a group of 100 observations were found to be 20 and 3, respectively. Later on it was found that three observations were incorrect, which were recorded as 21, 21 and 18. Find the mean and standard deviation if the incorrect observations are omitted.

Promotional Banner

Topper's Solved these Questions

  • STATISTICS

    NCERT GUJARATI|Exercise EXERCISE 15.3|3 Videos
  • SETS

    NCERT GUJARATI|Exercise MISCELLANEOUS EXERCISE ON CHAPTER 1|22 Videos
  • STRAIGHT LINES

    NCERT GUJARATI|Exercise Miscellaneous Exercise on Chapter 10|24 Videos

Similar Questions

Explore conceptually related problems

The mean and standard deviation of 20 observations are found to be 10 and 2, respectively. On rechecking , it was found that an observation 8 was incorrect . Calculate the correct mean and standard deviation in each of the following cases: (i) If wrong item is omitted. (ii) If it is replaced by 12.

The mean and standard deviation of a group of 200 candidates are 40 and 15 respectively. Later on it was found to that one observation 43 was incorrectly copied down as 34. find the correct mean and standard deviation.

Mean and standard deviation of 100 observations were found to be 40 and 10, respectively . If at the time of calculation two observation were wrongly taken as 30 and 70 in place of 3 and 27 respectively, find the correct standard deviation.

The mean and standard deviation of a set of n_1 observation are barx_1 and S_1 , respectively while the mean standard deviation of another set of n_2 observations are barx_2 and S_2 , respectively . Show that the standard deviation of the combined set of (n_1+n_2) observations is given by standard deviation sqrt ((n_1(S_1)^2 + n_1(S_2)^2)/(n_1+n_2) + (n_1+n_2 (barx_1 - barx_2)^2)/(n_1-n_2)^2)

The mean and standard deviation of 100 observation were calculated as 40 and 5.1, respectively by a student who took by mistake 50 instead of 40 for one observation . What are the correct mean standard deviation?

Mean and standard deviation of 100 items are 50 and 4, respectively . Find the sum of all the item and the sum of the squares of the items.

The mean and standard deviation of six observations are 8 and 4, respectively. If each observation is multiplied by 3, find the new mean and new standard deviation of the resulting observations

Mean and standard deviation of the random variable X are (7)/(3) and (14)/(9) respectively. Then find value of n and p.