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Let f: R-{-4/3}->Rbe a function as f(x)...

Let `f: R-{-4/3}->R`be a function as `f(x)=(4x)/(3x+4)`. The inverse of f is map, `g: R a ngef->R-{-4/3}`given by.(a) `g(y)=(3y)/(3-4y)` (b) `g(y)=(4y)/(4-3y)`(c) `g(y)=(4y)/(3-4y)` (d) `g(y)=(3y)/(4-3y)`

A

`g (y) = (3y)/(3-4y)`

B

`g (y) = (4y)/(4-3y)`

C

`g (y) = (4y)/(3-4y)`

D

`g (g) = (3y)/(4-3y)`

Text Solution

Verified by Experts

The correct Answer is:
B
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