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Given A=[sqrt(3)2""""""1 3""""""""-1 0] ...

Given `A=[sqrt(3)2""""""1 3""""""""-1 0]` and `B=[2-2""""""sqrt(5)3""""""""1 1/2]` , find `A" "+B` .

Text Solution

Verified by Experts

The correct Answer is:
`[(2+sqrt(3),1+sqrt(5),0),(0,6,(1)/(2))]`
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