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If A=[1 1 1 1 1 1 1 1 1], prove that A^n...

If `A=[1 1 1 1 1 1 1 1 1]`, prove that `A^n=[3^(n-1)3^(n-1)3^(n-1)3^(n-1)3^(n-1)3^(n-1)3^(n-1)3^(n-1)3^(n-1)], n in Ndot`

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