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If A=[alphabetagamma-alpha] is such that...

If `A=[alphabetagamma-alpha]` is such that `A^2=I` , then `1+alpha^2+betagamma=0` (b) `1-alpha^2+betagamma=0` (c) `1-alpha^2-betagamma=0` (d) `1+alpha^2-betagamma=0`

A

`I+alpha^(2)+beta gamma=0`

B

`I-alpha^(2)+beta gamma=0`

C

`I-alpha^(2)-beta gamma=0`

D

`I+alpha^(2)-beta gamma=0`

Text Solution

Verified by Experts

The correct Answer is:
C
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