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Find the maximum value and the minimum value and the minimum value of `3x^4-8x^3+12 x^2-48 x+25` on the interval `[0,3]dot`

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The correct Answer is:
Minima at x = 2, minimum value = – 39, Maxima at x = 0, maximum value = 25.
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NCERT GUJARATI-APPLICATION OF DERIVATIVES-EXERCISE 6.5
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