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The point on the curve x^2=2ywhich is ne...

The point on the curve `x^2=2y`which is nearest to the point (0, 5) is(A) `(2sqrt(2),4)` (B) `(2sqrt(2),0)` (C) (0, 0) (D) (2, 2)

A

`(2sqrt(2),4)`

B

`(2sqrt(2),0)`

C

`(0,0)`

D

(2,2)

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NCERT GUJARATI-APPLICATION OF DERIVATIVES-EXERCISE 6.5
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  17. Show that semi-vertical angle of right circular cone of given surface...

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  18. The point on the curve x^2=2ywhich is nearest to the point (0, 5) is(A...

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  20. The maximum value of [x(x-1)+1]^(1/3),0lt=xlt=1is(A) (1/3)^(1/3) (B) ...

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