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Find the equation of the normal to curve...

Find the equation of the normal to curve `x^2=4y`which passes through the point (1, 2).

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The correct Answer is:
x+y-3 =0
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NCERT GUJARATI-APPLICATION OF DERIVATIVES-EXERCISE 6.6
  1. Show that the function given by f(x)=(logx)/xhas maximum at x = e.

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  2. The two equal sides of an isosceles triangle with fixed base b are ...

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  3. Find the equation of the normal to curve x^2=4ywhich passes through t...

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  4. Show that the normal at any point theta to the curve x=acostheta+at...

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  5. Find the intervals in which the function f given by f(x)=(4sinx-2x-x c...

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  6. Find the intervals in which the function f given by f(x)=\ x^3+1/(...

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  7. Find the maximum area of an isosceles triangle inscribed in the ellip...

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  8. A tank with rectangular base and rectangular sides, open at the top...

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  9. The sum of the perimeter of a circle and square is k, where k is so...

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  10. A window is in the form of a rectangle surmounted by a semicircular...

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  11. A point on the hypotenuse of a triangle is at distance a and b from t...

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  12. Find the points at which the function f given by f(x)=(x-2)^4(x+1)^3 h...

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  13. Find the absolute maximum and minimum values of the function f give...

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  14. Show that the altitude of the right circular cone of maximum volume...

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  15. Let f be a function defined on [a, b] such that f^(prime)(x)>0, for al...

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  16. Show that the height of the cylinder of maximum volume that can be ...

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  17. Show that height of the cylinder of greatest volume which can be insc...

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  18. A cylindrical tank of radius 10 m is being filled with wheat at the r...

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  19. The slope of the tangent to the curve x=t^(2)+3t-8,y=2t^(2) -2t -5 at...

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  20. The line y = m x + 1is a tangent to the curve y^2=4xif the value of m...

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