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Find the area of the circle 4x^(2) + 4y^...

Find the area of the circle `4x^(2) + 4y^(2) = 9` which is interior to the parabola `x^(2) = 4y`.

Text Solution

Verified by Experts

The correct Answer is:
`sqrt2/6+9/4 sin^(-1) ""(2sqrt2)/(3)`
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Find the area lying above x-axis and included between the circle x^(2) + y^(2) = 8x and inside in the parabola y^(2) = 4x.

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Knowledge Check

  • The area of the circle x^(2) + y^(2) = 16 exterior to the parabola y = 6x is

    A
    `4/3(4pi-sqrt3)`
    B
    `4/3(4pi+sqrt3)`
    C
    `4/3(8pi-sqrt3)`
    D
    `4/3(8pi+sqrt3)`

  • The area of the circle x^2 +y^2 =16 exterior to the parabola y^2 = 6x is …..

    A
    `4/3 ( 4 pi - sqrt(3))`
    B
    `4/3 ( 4 pi + sqrt(3))`
    C
    `4/3 ( 8 pi - sqrt(3))`
    D
    `4/3 ( 8 pi + sqrt(3))`

    • Similar Questions

    Explore conceptually related problems

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    The directrix of the parabola x^2-4x-8y + 12=0 is

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    Find the area bounded by the curve x^(2) = 4y and the line x = 4y - 2.

    Find the eccentricity of the hyperbola 9y^(2) - 4x^(2) = 36 .

    Find the area of the region {(x, y) : y^(2) le 4x, 4x^(2) + 4y^(2) le 9}

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