`y - cos y = x : (y sin y + cos y + x)y' = y`

y = cos x + C : y' + sin x = 0

(cos x + cos y ) ^(2) + (sin x - sin y ) ^(2) = 4 cos ^(2) ""(x + y )/( 2)

(cos x- cos y) ^(2) + (sin x - sin y) ^(2) =4 sin ^(2) "" ( x-y)/(2)

The area of the region enclosed by the curves y= sin x, y = cos and x=0 , x = (3pi)/(2) is ……Sq. units.

Solve the differential equation (x dy - y dx) y sin ((y)/(x)) = (y dx + x dy) x cos ((y)/(x)) .

lf cos x + cosy-cos z = 0 = sin x + sin y + sin z then cos((x-y)/2)=

Find (dy)/(dx) if y+ sin y= cos x

y = e^(x)(a cos x + b sin x)

Obtain the particular solution of the differential equation: { x cos ((y)/( x)) + y sin ((y)/( x))} ydx= { y sin ((y)/( x) ) - x cos ((y)/( x))}xdy where : x=2 when y= (pi)/(2) .

Find the value of 'a' which the system of equation sin x * cos y=a^(2) and sin y* cos x =a have a solution