Show `(veca-vecb)x(veca+vecb)=2(vecaxxvecb)`

Find |veca|and|vecb| , if (veca+vecb)*(veca-vecb)=8and|veca|=8|vecb| .

Prove that (veca+vecb)*(veca+vecb)=|veca|^(2)+|vecb|^(2) , if and only if veca,vecb are perpendicular , given vecanevec0,vecbnevec0 . Choose the correct answer in Exercises 16 to 19.

Let veca=hati+ hatj and vecb = 2hati-hatk . The point of intersection of the lines vecrxxveca= vecbxxveca and vecrxxvecb=vecaxxvecb is

If theta is the angle between any two vectors vecaandvecb , then |veca*vecb|=|vecaxxvecb| when theta is equal to

If veca and vecb are two non collinear unit vectors and iveca+vecbi=sqrt(3) then find the value of (veca-vecb).(2veca+vecb)

Evaluate the product (3veca-5vecb)*(2veca+7vecb) .

If veca, vecb and vecc are position vectors of A,B, and C respectively of DeltaABC and if|veca-vecb|,|vecb-vec(c)|=2, |vecc-veca|=3 , then the distance between the centroid and incenter of triangleABC is

What is the value of (vecA + vecB) * ( vecA xx vecB) ?

If (|veca+vecb|)/(|veca-vecb|)=1 , then angle between bar(a)" and "bar(b) is :-

(vecA+2vecB).(2vecA-3vecB) :-