Home
Class 9
PHYSICS
A bus is moving with the initial velocit...

A bus is moving with the initial velocity of 'u' m/s. After applying the breaks, its retardation is 0.5 m/`s^(2)` and it stoped after 12s. Find the initial velocity (u) and distance travel by the bus after applying the breaks.

Text Solution

Verified by Experts

a = 0.5 `m//s^(2)`
v = 0 m/s
t = 12 s
u = ?
v = u + at
0 = u + `(-0.5 xx 12 )`
0 = u - 6
u = 6 m/s
Initial velocity of the bus 6 m/s .
s = ut + `(1)/(2) at^(2)`
= `( 12 xx 6 ) + (1)/(2) ( - 0.5 xx 12^(2) )`
= 72 -` (1)/(2) (72)`
= 36 m
Bus has stoped 36 m distance after applying the break
Promotional Banner

Topper's Solved these Questions

  • MOTION

    NCERT GUJARATI|Exercise LET US IMPROVE OUR LEARNING (REFLECTIONS ON CONCEPTS )|7 Videos

  • MOTION

    NCERT GUJARATI|Exercise LET US IMPROVE OUR LEARNING(APPLICATION OF CONCEPTS)|7 Videos

  • LAW OF MOTION

    NCERT GUJARATI|Exercise LET US IMPROVE OUR LEARNING (MULTIPLE CHOICE QUESTIONS )|5 Videos

  • REFRACTION OF LIGHT AT PLANE SURFACES

    NCERT GUJARATI|Exercise THINK AND DISCUSS|2 Videos

Similar Questions

Explore conceptually related problems

A car is moving with the initial velocity 15 m/s. Car stoped after 5s by application of breaks. Find the retardation (Decelaration).

What will be distance covered byu vehicle after applying breakes with retardation 8 m//s ^(2) if its velocity is 72 km/h ?

What will be distance covered by vehicle after applying brakes with retardation 2m //s^(2) if its velocity is 1.8 km//h ?

The velocity acquired by a body moving with uniformaccelertion is 30 m s^(-1) in 2s and 60 ms ^(-1) in 4 s , The initial velocity is .

A car is moving with a constant acceleration and initial velocity 2 ms^(-1) on a straight path. After 10 s it attains the velocity 12 ms^(-1). Then find the distance covered by it in this 10 s.

A particle starts with an initial velocity 2.5 m//s along the posiive x-direction and it accelerates uniformly at the rate 0.50 m//s^2. Find the distance travelled by it in the first two seconds

A pebble is thrown vertically upwards from a bridge with an initial velocity of 4.9 m/s. It strikes the water after 2s. If acceleration due to gravity is 9.8 m//s^(2)(a) what is the height of the bridge? (b) with what velocity does that pebble strike the water?

A particle is moving along a straight line along x-zxis with an initial velocity of 2 m//s towards positive x-axis. A constant acceleration of 0.5 m//s^(2) towards negative x-axis starts acting on particle at t=0 . Find velocity (in m//s ) of particle at t=2 s .