A piece of iron when placed on a block of wood, this makes the wood to float lower in the water. If the iron piece is suspended beneath the wood block, would it float at the same depth? Or lower or higher?
You know that pressure difference at different levels inside the liquid causes buoyancy.

A block of wood floats in water with (4//5)th of its volume submerged. If the same block just floats in a liquid, the density of liquid in (kg m^(-3)) is

The total weight of a piece of wood is 6 kg in the floating state in water its 1/3 part remains inside the water on this floating solid what maximum weight is to be put such that the whole of the piece of wood is to be drowned in the water

A cubical block of wood of edge 3 cm floats in water. The lower surface of the cube just touches the free end of a vertical spring fixed at the bottom of the pot. Find the maximum weight that can be put on the block without wetting it. Density of wood = 800 kgm^-3 and spring constant of the spring =50Nm^-1 Take g=10ms^-2 . ,

A cylindrical of wood (density = 600 kg m^(-3) ) of base area 30 cm^(2) and height 54 cm , floats in a liquid of density 900 kg^(-3) The block is displaced slightly and then released. The time period of the resulting oscillations of the block would be equal to that of a simple pendulum of length (nearly) :