The work done by a force `F_1` is larger than the work done by another force `F_2`. Is it neccesary that power delivered by `F_1` is also larger than that of `F_2` ? Why

A body of mass 2 kg initially kg intially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1 Compute the (a) work done by the applied force in 10 s. (b) work done by friction in 10 s . work done by the net force on the body in 10 s. (d) Change in kinetic energy of the body in 10 s and interpret your details .

If the work done on an object is 10 J and the object is displaced through 2 m, then what is the force applied?

A force F acting on a body depends on its displacement x as Fpropx^(a) . The power delivered by F will be independent of x if n is -

A body is displaced by 2m in Z - direction by a force (-4,2,6)N . Find the work done ……….

Two wires of same diameter of the same material having the length l and 2l If the force F is applied on each, the ratio of the work done in two wires will be

Two force F_(1)" and "F_(2) are acting on a body. One force is double that of the other force and the resultant is equal to the greater force. Then the angle between the two forces is :-

Assertion :- when two non parallel forces F_(1) and F_(2) act on a body. The magnitude of the resultant force acting on the is less than the "sum" of F_(1) and F_(2) Reason :- In a triangle, any side is less then the "sum" of the other two sides.