If 50g of water at `20^@` C temperature and 50 g of water `40^@` C temperature are mixed, what is the final temperature of the mixture of?

2g ice at 0^(@)C is mixed with 1 g steam at 100^(@)C . Find the final temperature of the mixture.

540 g of ice at 0^(@)C is mixed with 540 g of water at 80^(@)C . The final temperature of the mixture is

100g of ice at 0^(@) is mixed with 100g of water at 100^(@)C . What will be the final temperature (in K ) of the mixture?

In a insulated vessel, 0.05 kg steam at 373 K and 0.45 kg of ice at 253 K are mixed. Find the final temperature of the mixture (in kelvin.) Given, L_(fusion) = 80 cal//g = 336 J//g L_("vaporization") = 540 cal//g = 2268 J//g s_(ice) = 2100 J//kg.K = 0.5 cal//g.K and s_("water") = 4200 J//kg.K = 1cal//g.K .

When two non reactive samples at different temperatures are mixed in an isolated container of negligible heat capacity the final temperature of the mixture can be:

A 10 g ice cube is dropped into 45 g of water kept in a glass. If the water was initially at a temperature of 28^(@)C and the temperature of ice -15^(@)C , find the final temperature (in ^(@)C ) of water. (Specific heat of ice =0.5" "cal//g-""^(@)C" and "L=80" "cal//g)

100 g of ice (latent heat 80 cal/g, at 0^(@)C ) is mixed with 100 g of water (specific heat 1" cal"//g-""^(@)C ) at 80^(@)C . The final temperature of the mixture will be :-

Steam is passes into 22 g of water at 20^@C . The mass of water that will be present when the water acquires a temperature of 90^@C , (Latent heat of steam is 540 cal//g ) is