Home
Class 11
PHYSICS
The Sun's angular diameter is measured t...

The Sun's angular diameter is measured to be 1920". The distance D of the Sun from the Earth is `1.496xx109^(11)` m. What is the diameter of the Sun ?

Text Solution

Verified by Experts

Sun.s angular diameter `alpha`
1920"
`=1920xx4.85xx10^(-6)`rad
`9.31xx10^(-3)` rad
Sun.s diameter
`d = alphaD`
`=(9.31xx10^(-3))xx(1.496xx10^(11))`m
`=1.39xx10^(9)m`
Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENT

    NCERT GUJARATI|Exercise Exercise (Fill in the blanks)|8 Videos
  • UNITS AND MEASUREMENT

    NCERT GUJARATI|Exercise EXERCISE|26 Videos
  • THERMODYNAMICS

    NCERT GUJARATI|Exercise EXERCISES|10 Videos
  • WAVES

    NCERT GUJARATI|Exercise Exercises|27 Videos

Similar Questions

Explore conceptually related problems

The Sun's angular diameter is 30''. The distance of Earth from Sun is 1.496xx10^(11) m , then find the diameter of the Sun. (1''= 4.85xx10^(-6) rad)

The Jupitar's angular diameter is 35.72'' . The distance of Earth from Jupiter is 82.27xx10^(6) km then find diameter of the jupiter.

A boy focuses Sunlight on a paper by using biconvex lens of focal length 10 cm. Such that paper can be burnt. Diameter of Sun is 1.39 xx 10^9 m and distance of Earth from Sun is 1.5 xx 10^(11) m approximately, then the diameter of image of Sun on paper will be

The sun (diameter d ) subtends an angle theta radian at the pole of a concave mirror of focal length f . What is the diameter of the image of the sun formed by the mirror ?

A saturn year is 29.5 times the earth year. How far is the saturn from the sun if the earth is 1.50 × 10^(8) km away from the sun ?

The diameter of the sun subtends an angle of 0.5^(@) at the pole of the concave mirror. The radius of curvature of the mirror is 1.5 m. Find the diameter of the image of the sun. Consider the distance of sun from the mirror infinite

The principle of 'parallax' in section 2.3.1 is used in the determination of distances of very distant starts. The baseline AB is the line joining the Earth's two locations six months apart in its orbit around the Sun. That is, the baseline is about the diameter of the Earth's orbit = 3xx10^(11)m . However, even the nearest stars are so distant that with such a long baseline, they show parallax only of the order of 1" (second) of arc or so. A parsec is a conventent unit of length on the astronomical scale. It is the distance of an object that will show a parallax of 1" (second of arc) from opposite ends of a baseline equal to the distance from the Earth to the Sun. How much is a parsec in terms of metres ?

The height of a tower is 10m. What is the length of its shadow when the Sun's altitiude is 45^(@) ?

The planet is observed from two diametrically opposite points A and B on Eath. The angle theta subtended at the planet by the two directions of observation is 1^(@)30' . Given the diameter of the Earth to be about 1.276xx10^(7)m , computer the distance of the moon from the Earth.

A heavenly body is observed from two diametrically opposite points A and B on the earth. The angle substended at the heavenly body is 2.9 xx 10^(-4) rad. Given the diameter of Earth to be about 1.28 xx 10^(7) Compute the distance of the heavenly body from the earth.