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G = 6.67xx10^(-11) N m^(2)(kg)^(-2) = ……...

`G = 6.67xx10^(-11) N m^(2)(kg)^(-2) = ………. (cm)^(3)s^(-2)g^(-1)`.

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`6.67xx10^(-8)`
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1 kg m^(2)s^(-2) =………. g cm^(2) s^(-2)

If in a system the force of attraction between two point masses of 1kg each situated 1km apart is taken as a unit force and is called newton(newton written in reverse order) If G = 6.67 xx 10^(-11) N-m^(2)kg^(-2) in \SI units, the relation of newton and newton is

On earth, the value of G = 6.67 xx 10^(-11) Nm^(2)// kg^(2) . What is its value on the moon ?

A rocket is fired vertically with a speed of 5 km s^(-1) from the earth’s surface. How far from the earth does the rocket go before returning to the earth ? Mass of the earth = 6.0 × 10^(24) kg, mean radius of the earth = 6.4 xx 10^(6) m , G = 6.67 xx 10^(-11) " N "m^(2) kg^(-2) .

A spaceship is stationed on Mars. How much energy must be expended on the spaceship to launch it out of the solar system ? Mass of the space ship = 1000 kg, mass of the sun = 2 xx 10^(30) kg , mass of mars = 6.4 xx 10^(23) kg, radius of mars = 3395 Km: radius of the orbit of mars = 2.28 xx 10^(8) km , G = 6.67 xx 10^(-11) N m^(2) kg^(-2) .

The time period of revolution of moon around the earth is 28 days and radius of its orbit is 4xx10^(5) km. If G=6.67xx10^(-11) Nm^(2)//kg^(2) then find the mass of the earth.

Give the order of the following : (a) 1 (b) 1000 (c ) 499 (d) 500 (e) 501) (f) 1 AU (1.496 xx 10^(11) m) (g) 1 Å (10(-10)m ) (h) Speed of light (3.00 xx 10^(8) m//s) (i) Gravitational constant (6.67 xx 10^(-11) N-m^(2)//kg^(2)) (j) Avogadro constant (6.02 xx 10^(23) mol^(-1)) (k) Planck's constant (6.63 xx 10^(-34) J-s) (l) Charge on electron (1.60 xx 10^(-19) C) (m) Radius of H - atom (5.29 xx 10^(-11)m) (n) Atmospheric pressure (1.01 xx 10^(5) Pa) (o) Mass of earth (5.98 xx 10^(24)kg) (p) Mean radius of earth (6.37 xx 10^(6)m)

The position vector of the objects of masses 25 kg and 10 kg are (4,7,5)m and (1,3,5) m respectively. Obtain the vector representing the gravitational force on 25 kg object by 10 kg object. (Take G = 6.67 xx 10^(-11) Nm^(2)kg^(-2) )

A rocket is fired ‘vertically’ from the surface of mars with a speed of 2 km s^(–1) . If 20% of its initial energy is lost due to martian atmospheric resistance, how far will the rocket go from the surface of mars before returning to it ? Mass of mars = 6.4 xx 10^(23) kg, radius of mars = 3395 km, G = 6.67 xx 10^(-11) N m^(2) Kg^(-2) .