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The motion of a particle of mass m is de...

The motion of a particle of mass m is described by `y = ut + 1/2 "gt"^2` . Find the force acting on the particle.

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We know
`y = ut + 1/2 "gt"^2`
`v = (dy)/(dt) = u + "gt"`
`a = (dv)/(dt) = g`
Then the force is given by eq.
F = ma = mg
Thus the given equation describes the motion of a particle under acceleration due to gravity and y is the position coordinate in the direction of g.
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NCERT GUJARATI-LAW OF MOTION-EXERCISE (ADDITIONAL EXERCISE)
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  2. Figure shows the position-time graph of a body of mass 0.04 kg. Sugg...

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  3. Figure shows a man standing stationary with respect to a horizontal c...

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  4. A stone of mass m tied to the end of a string revolves in a vertical c...

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  5. A helicopter of m ass 1000 kg rises with a vertical a c c ele ra tio n...

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  6. A stream of water flowing horizontally with a speed of 15 m s'1 gushes...

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  7. Ten one-rupee coins are put on top of each other on a table. Each coi...

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  8. An aircraft executes a horizontal loop at a speed of 720 km/h with its...

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  9. A train runs along an unbanked circular track of radius 30 m at a spee...

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  10. A block of mass 25 kg is raised by a 50 kg man in two different ways a...

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  11. A monkey of mass 40 kg climbs on a rope. which can stand a maximum ten...

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  12. Two bodies A and B of masses 5 kg and 10 kg in contact with each othe...

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  13. A block of mass 15 kg is placed on a long trolley. The coefficient of ...

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  14. The rear side of a truck is open and a box of 40 kg mass is placed 5 m...

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  15. A disc revolves with a speed of 33 1/3 rev/min. 3 and has radius of 1...

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  16. You may have seen in a circus a motorcyclist driving in vertical loops...

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  17. A 70 kg man stands in contact against the inner wall of a hollow cylin...

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  18. A thin circular loop of radius R rotates about its vertical diameter w...

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