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Examine Tables 61. -6.3 and express (a) ...

Examine Tables 61. -6.3 and express (a) the energy required to break one bond in DNA in eV, (b) The kinetic energy of an air molecule `(10^(-21)J)` in eV , (c ) The daily intake of a human adult in kilocalories .

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The kinetic energy of an air molecule is
`(10^(-21)J)/(1.6xx10^(-19)J"/"eV) cong 0.0062 eV`
This is the same as 6.2 meV.
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