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An elevator can carry a maximum load of ...

An elevator can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a constant speed of `2ms^(-1)`. The frictional force opposing the motion is 4000 N. Determine the minimum power delivered by the motor to the elevator in watts as well as in horse power.

Text Solution

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The downward force on the elevator is `F= mg+ F_(f)= (1800xx10)+ 4000= 22000N`
The motor must supply enough power to balance this force. Hence,
`P= F*v= 22000xx2= 44000 W = 59 hp`.
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