A body of mass 2 kg initially kg intially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = `0.1 ` Compute the
(a) work done by the applied force in 10 s.
(b) work done by friction in 10 s .
work done by the net force on the body in 10 s.
(d) Change in kinetic energy of the body in 10 s and interpret your details .

Explanation

`882 J` Work done by the net force on a body equals change in its kinetic energy.