What is the pressure inside the drop of mercury of radius 3.00mm at room temperature? Surface tension of mercury at that temperature `(20^@C)` is `4.65 times 10^-1 N m^-1`. The atmospheric pressure is `1.01 times 10^5 Pa`. Also give the excess pressure inside the drop.

Explanation

Excess pressure =310Pa.total pressure `=1.0131 times 10^5 Pa`. However, since data are correct to three significant figures. We should write total pressure inside the drop as `1.01 times 10^5Pa`.