Obtain the equivalent capacitance of the network in Fig. 2.33. For a 300 V supply, determine the charge and voltage across each capacitor.

Explanation

Equivalent capacitance = (200/3) pF.
`Q_(1) = 10^(-8) C, V_(1) = 100 V: Q_(2) = Q_(3) = 10^(-8)` C
`V_(2) =V_(3) = 50 V`
`Q_(4) = 2.55 xx 10^(-8) C, V_(4) = 200 V`