Home
Class 12
PHYSICS
The earth's field departs from its dipol...

The earth's field departs from its dipole shape substantially at large distances (greater than about 30.000 km). What agencies may be responsible for this distortion?

Promotional Banner

Topper's Solved these Questions

  • MAGNETISM AND MATTER

    NCERT GUJARATI|Exercise Additional Exercises|19 Videos
  • MAGNETISM AND MATTER

    NCERT GUJARATI|Exercise Additional Exercises|19 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NCERT GUJARATI|Exercise EXERCISES|35 Videos
  • MOVING CHARGES AND MAGNETISM

    NCERT GUJARATI|Exercise ADDITIONAL EXERCISES|17 Videos

Similar Questions

Explore conceptually related problems

A short bar magnet of magnetic moment 5.25 xx 10^(-2) JT^(-1) is placed with its axis perpendicular to the earth's field direction. At what distance from the centre of the magnet, the resultant field is inclined at 45^@ with earth's field on (a) its normal bisector and (b) its axis. Magnitude of the earth's fleld at the place is given to be 0.42 G. Ignore the length of the magnet in comparison to the distances involved.

An accelration produces a narrow beam of protons, each having an initial speed of v_(0) . The beam is directed towards an initially uncharges distant metal sphere of radius R and centered at point O. The initial path of the beam is parallel to the axis of the sphere at a distance of (R//2) from the axis, as indicated in the diagram. The protons in the beam that collide with the sphere will cause it to becomes charged. The subsequentpotential field at the accelerator due to the sphere can be neglected. The angular momentum of a particle is defined in a similar way to the moment of a force. It is defined as the moment of its linear momentum, linear replacing the force. We may assume the angular momentum of a proton about point O to be conserved. Assume the mass of the proton as m_(P) and the charge on it as e. Given that the potential of the sphere increases with time and eventually reaches a constant velue. One the potential of the sphere has reached its final, constant value, the minimum speed v of a proton along its trajectory path is given by

An accelration produces a narrow beam of protons, each having an initial speed of v_(0) . The beam is directed towards an initially uncharges distant metal sphere of radius R and centered at point O. The initial path of the beam is parallel to the axis of the sphere at a distance of (R//2) from the axis, as indicated in the diagram. The protons in the beam that collide with the sphere will cause it to becomes charged. The subsequentpotential field at the accelerator due to the sphere can be neglected. The angular momentum of a particle is defined in a similar way to the moment of a force. It is defined as the moment of its linear momentum, linear replacing the force. We may assume the angular momentum of a proton about point O to be conserved. Assume the mass of the proton as m_(P) and the charge on it as e. Given that the potential of the sphere increases with time and eventually reaches a constant velue. The limiting electric potential of the sphere is

An accelration produces a narrow beam of protons, each having an initial speed of v_(0) . The beam is directed towards an initially uncharges distant metal sphere of radius R and centered at point O. The initial path of the beam is parallel to the axis of the sphere at a distance of (R//2) from the axis, as indicated in the diagram. The protons in the beam that collide with the sphere will cause it to becomes charged. The subsequentpotential field at the accelerator due to the sphere can be neglected. The angular momentum of a particle is defined in a similar way to the moment of a force. It is defined as the moment of its linear momentum, linear replacing the force. We may assume the angular momentum of a proton about point O to be conserved. Assume the mass of the proton as m_(P) and the charge on it as e. Given that the potential of the sphere increases with time and eventually reaches a constant velue. If the initial kinetic energy of a proton is 2.56 ke V , then the final potential of the sphere is

An accelration produces a narrow beam of protons, each having an initial speed of v_(0) . The beam is directed towards an initially uncharges distant metal sphere of radius R and centered at point O. The initial path of the beam is parallel to the axis of the sphere at a distance of (R//2) from the axis, as indicated in the diagram. The protons in the beam that collide with the sphere will cause it to becomes charged. The subsequentpotential field at the accelerator due to the sphere can be neglected. The angular momentum of a particle is defined in a similar way to the moment of a force. It is defined as the moment of its linear momentum, linear replacing the force. We may assume the angular momentum of a proton about point O to be conserved. Assume the mass of the proton as m_(P) and the charge on it as e. Given that the potential of the sphere increases with time and eventually reaches a constant velue. After a long time, when the potential of the sphere reaches a constant value, the trajectory of proton is correctly sketched as

An accelration produces a narrow beam of protons, each having an initial speed of v_(0) . The beam is directed towards an initially uncharges distant metal sphere of radius R and centered at point O. The initial path of the beam is parallel to the axis of the sphere at a distance of (R//2) from the axis, as indicated in the diagram. The protons in the beam that collide with the sphere will cause it to becomes charged. The subsequentpotential field at the accelerator due to the sphere can be neglected. The angular momentum of a particle is defined in a similar way to the moment of a force. It is defined as the moment of its linear momentum, linear replacing the force. We may assume the angular momentum of a proton about point O to be conserved. Assume the mass of the proton as m_(P) and the charge on it as e. Given that the potential of the sphere increases with time and eventually reaches a constant velue. The total energy (E) of a proton in the beam travelling with seed v at a distance of r (r ge R) from point O. Assuming that the sphere has acquired an electrostatic charge Q is

When a particle is undergoing motion, the diplacement of the particle has a magnitude that is equal to or smaller than the total distance travelled by the particle. In many cases the displacement of the particle may actually be zero, while the distance travelled by it is non-zero. Both these quantities, however depend on the frame of reference in which motion of the particle is being observed. Consider a particle which is projected in the earth's gravitational field, close to its surface, with a speed of 100sqrt(2) m//s , at an angle of 45^(@) with the horizontal in the eastward direction. Ignore air resistance and assume that the acceleration due to gravity is 10 m//s^(2) . There exists a frame (D) in which the distance travelled by the particle is minimum. This minimum distance is equal to :-

A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth's magnetic Meld at the place is 0.36 G and the angle of dip 18 zero. What is the total magnetic feld on the normal bisector of the magnet at the same distance as the mull-point (i.e., 14 cm) from the centre of the magnet? At rull points, field due to a magnet 1s equal and opposite to the horizontal component of earth's magnetic field.)

A compass needle free to turn in a horizontal plane is placed at the centre of circular coil of 30 turns and radius 12 cm. The coil is in a vertical plane making an angle of 45° with the magnetic meridian. When the current in the coil is 0.35 A, the needle points west to east. (a) Determine the horizontal component of the earth's magnetic field at the location. (b) The current in the coil is reversed, and the coil is rotated about its vertical axis by an angle of 90° in the anticlockwise sense looking from above. Predict the direction of the needle. Take the magnetic declination at the places to be zero.

NCERT GUJARATI-MAGNETISM AND MATTER-Exercises
  1. Answer the question regarding earth's magnetism: Geologists claim t...

    Text Solution

    |

  2. The earth's magnetic field varies from point to point in space. Does i...

    Text Solution

    |

  3. The earth's core is known to contain tron. Yet geologists do not regar...

    Text Solution

    |

  4. The charged currents in the outer conducting regions of the earth's co...

    Text Solution

    |

  5. The earth may have even reversed the direction of its field several um...

    Text Solution

    |

  6. The earth's field departs from its dipole shape substantially at large...

    Text Solution

    |

  7. Interstellar space has an extremely weak magnetic field of the order o...

    Text Solution

    |

  8. A short bar magnet placed with its axis at 30^(@) with a uniform exter...

    Text Solution

    |

  9. A short bar magnet of magnetic moment m=0.32 JT^(-1) is placed in a un...

    Text Solution

    |

  10. A closely wound solenoid of 800 turns and area of cross section 25 xx ...

    Text Solution

    |

  11. If the solenoid in Exercise 5.5 is free to tum about the vertical dire...

    Text Solution

    |

  12. A bar magnet of magnetic moment 1.5 JT^(-1) lies aligned with the dire...

    Text Solution

    |

  13. A closely wound solenoid of 2000 turns and area of cross-section 1.6 x...

    Text Solution

    |

  14. A circular coil of 16 turns and radius 10 cm carrying a current of 0.7...

    Text Solution

    |

  15. A magnetic needle free to rotate in a vertical plane parallel to the m...

    Text Solution

    |

  16. At a certain location in Africa, a compass points 12^@ west of the geo...

    Text Solution

    |

  17. A short bar magnet has a magnetic moment of 0.48 JT^(-1). Give the dir...

    Text Solution

    |

  18. A short bar magnet placed in a horizontal plane has its axis aligned a...

    Text Solution

    |

  19. If the bar magnet in exercise 5.13 is turned around by 180^@, where wi...

    Text Solution

    |

  20. A short bar magnet of magnetic moment 5.25 xx 10^(-2) JT^(-1) is place...

    Text Solution

    |