Home
Class 12
PHYSICS
The nucleus ""(10)^(23)Ne decays by beta...

The nucleus `""_(10)^(23)Ne` decays by `beta^(-)`– mission. Write down the `beta`-decay equation and determine the maximum kinetic energy of the electrons emitted. Given that:
`m (""_(10)^(23)Ne ) = 22.994466 u`
`m (""_(11)^(23)Na ) = 22.989770 u. `

Text Solution

Verified by Experts

`""_(10)^(23)Ne to ""_(11)^(23)Na + e^(-) + bar(v) + Q , Q = [m_N (""_(10)^(23)Ne) - m_N (""_(11)^(23)Na) - m_(e)] c^2`, where the masses used are masses of nuclei and not of atoms as in Exercise . Using atomic masses `Q = [m (""_(10)^(23)Ne) - m(""_(11)^(23)Na)]c^2`. Note `m_e` has been cancelled. Using given masses, `Q = 4.37 MeV`. As in Exercise , maximum kinetic energy of the electron (max `E_e) = Q = 4.37 MeV`.
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    NCERT GUJARATI|Exercise ADDITIONAL EXERCISES|9 Videos

  • NUCLEI

    NCERT GUJARATI|Exercise ADDITIONAL EXERCISES|9 Videos

  • MOVING CHARGES AND MAGNETISM

    NCERT GUJARATI|Exercise ADDITIONAL EXERCISES|17 Videos

  • RAY OPTICS AND OPTICAL INSTRUMENTS

    NCERT GUJARATI|Exercise EXERCISES|40 Videos

Similar Questions

Explore conceptually related problems

.^(23)Ne decays to .^(23)Na by negative beta emission. What is the maximum kinetic energy of the emitter electron ?

The radionuclide ""^(11)C decays according to ""_(6)^(11)C to ""_(5)^(11) B + e^(+) + v, T_(1//2) = 20.3 min The maximum energy of the emitted positron is 0.960 MeV. Given the mass values: m ( ""_(6)^(11)C) = 11.011434 u and m (""_(6)^(11)B ) = 11.009305 u, calculate Q and compare it with the maximum energy of the positron emitted.

The isotope _(5)^(12) B having a mass 12.014 u undergoes beta - decay to _(6)^(12) C _(6)^(12) C has an excited state of the nucleus ( _(6)^(12) C ^(**) at 4.041 MeV above its ground state if _(5)^(12)E decay to _(6)^(12) C ^(**) , the maximum kinetic energy of the beta - particle in unit of MeV is (1 u = 931.5MeV//c^(2) where c is the speed of light in vaccuum) .

Consider the fission of ""_(92)^(238)U by fast neutrons. In one fission event, no neutrons are emitted and the final end products, after the beta decay of the primary fragments, are ""_(58)^(140)Ce and ""_(44)^(99)Ru . Calculate Q for this fission process. The relevant atomic and particle masses are m(""_(92)^(238)U) =238.05079 u m( ""_(58)^(140)Ce ) =139.90543 u m(""_(44)^(99)Ru ) = 98.90594 u

The Q value of a nuclear reaction A + b to C + d is defined by Q = [m_A + m_b – m_C – m_d]c^2 where the masses refer to the respective nuclei. Determine from the given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic. (i) ""_(1)^(1)H + ""_(1)^(3)H to _(1)^(2)H + _(1)^(2)H (ii) ""_(6)^(12)C + ""_(6)^(12)C to ""_(10)^(20)Ne + ""_(2)^(4)He Atomic masses are given to be m (""_(1)^(2)H) = 2.014102 u m (""_(1)^(3)H) = 3.016049 u m (""_(6)^(12)C ) = 12.000000 u m (""_(10)^(20)Ne ) = 19.992439 u .

A nucleus at rest undergoes a decay emitting an a particle of de - Broglie wavelength lambda = 5.76 xx 10^(-15)m if the mass of the daughter nucleus is 223.610 amu and that of alpha particle is 4.002amu , determine the total kinetic energy in the final state Hence , obtain the mass of the parent nucleus in amu (1 amu = 931.470 MeV//e^(2) )

Find the Q-value and the kinetic energy of the emitted a-particle in the a-decay of (a) ""_(88)^(226)Ra and (b) (86)^(220)Rn . Given m (""_(88)^(226)Ra) = 226.02540 u, " " m (""_(86)^(222)Rn) = 222.01750 u , m (""_(86)^(220)Rn) = 220.01137u, " " m(""_(84)^(216) Po) = 216.00186u .

A string of length 1 m fixed one end and on the other end a block of mass M = 4 kg is suspended. The string is set into vibration and represented by equation y =6 sin ((pi x)/(10)) cos (100 pi t) where x and y are in cm and t is in seconds. (i) Find the number of loops formed in the string. (ii) Find the maximum displacement of a point at x = 5//3 cm (iii) Calculate the maximum kinetic energy of the string. (iv) Write down the equations of the component waves whose superposition given the wave. .

Two metallic plate A and B , each of area 5 xx 10^(-4)m^(2) , are placed parallel to each at a separation of 1 cm plate B carries a positive charge of 33.7 xx 10^(-12) C A monocharonatic beam of light , with photoes of energy 5 eV each , starts falling on plate A at t = 0 so that 10^(16) photons fall on it per square meter per second. Assume that one photoelectron is emitted for every 10^(6) incident photons fall on it per square meter per second. Also assume that all the emitted photoelectrons are collected by plate B and the work function of plate A remain constant at the value 2 eV Determine (a) the number of photoelectrons emitted up to i = 10s, (b) the magnitude of the electron field between the plate A and B at i = 10 s, and (c ) the kinetic energy of the most energotic photoelectrons emitted at i = 10 s whenit reaches plate B Negilect the time taken by the photoelectrons to reach plate B Take epsilon_(0) = 8.85 xx 10^(-12)C^(2)N- m^(2)

The mass of a nucleus ._(Z)^(A)X is less that the sum of the masses of (A-Z) number of neutrons and Z number of protons in the nucleus.The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of masses m_(1) and m_(2) only if (m_(1)+m_(2)) lt M . Also two light nuclei of masses m_(3) and m_(4) can undergo complete fusion and form a heavy nucleus of mass M'. only if (m_(3)+m_(4)) gt M' . The masses of some neutral atoms are given in the table below: |{:(._(1)^(1)H ,1.007825u , ._(1)^(2)H,2.014102u,._(1)^(3)H,3.016050u,._(2)^(4)He,4.002603u),(._(3)^(6)Li,6.015123u,._(3)^(7)Li,7.016004u,._(30)^(70)Zn,69.925325u, ._(34)^(82)Se,81.916709u),(._(64)^(152)Gd,151.91980u,._(82)^(206)Pb,205.974455u,._(83)^(209)Bi,208.980388u,._(84)^(210)Po,209.982876u):}| Taking kinetic energy ( in KeV ) of the alpha particle, when the nucleus ._(84)^(210)P_(0) at rest undergoes alpha decay, is:

NCERT GUJARATI-NUCLEI-EXERCISE
  1. Obtain the binding energy (in MeV) of a nitrogen nucleus (""(7)^(14)N)...

    Text Solution

    |

  2. Obtain the binding energy of the nuclei ""(26)^(26)Fe and ""(83)^(209)...

    Text Solution

    |

  3. A given coin has a mass of 3.0 g. Calculate the nuclear energy that wo...

    Text Solution

    |

  4. Write nuclear reaction equations for {:((i) a-"decay of " (88)^(226)...

    Text Solution

    |

  5. A radioactive isotope has a half-life of T years. How long will it tak...

    Text Solution

    |

  6. The normal activity of living carbon-containing matter is found to be ...

    Text Solution

    |

  7. Obtain the amount of ""(27)^(60)Co necessary to provide a radioactive ...

    Text Solution

    |

  8. The half-life of ""(38)^(90)Sr is 28 years. What is the disintegration...

    Text Solution

    |

  9. Obtain approximately the ratio of the nuclear radii of the gold isotop...

    Text Solution

    |

  10. Find the Q-value and the kinetic energy of the emitted a-particle in t...

    Text Solution

    |

  11. The radionuclide ""^(11)C decays according to ""(6)^(11)C to ""(5)^(...

    Text Solution

    |

  12. The nucleus ""(10)^(23)Ne decays by beta^(-)– mission. Write down the ...

    Text Solution

    |

  13. The Q value of a nuclear reaction A + b to C + d is defined by Q =...

    Text Solution

    |

  14. Suppose, we think of fission of a ""(26)^(56)Fe nucleus into two equal...

    Text Solution

    |

  15. The fission properties of ""(94)^(239)Pu are very similar to those of ...

    Text Solution

    |

  16. A 1000 MW fission reactor consumes half of its fuel in 5.00 y. How muc...

    Text Solution

    |

  17. How long can an electric lamp of 100W be kept glowing by fusion of 2.0...

    Text Solution

    |

  18. Calculate the height of the potential barrier for a head on collision ...

    Text Solution

    |

  19. From the relation R = R0A^(1//3), where R0 is a constant and A is the ...

    Text Solution

    |

  20. For the b+ (positron) emission from a nucleus, there is another compet...

    Text Solution

    |