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The neutron separation energy is defined...

The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energies of the nuclei `""_(20)^(41)Ca and ""_(13)^(27)Al` from the following data:
`m(""_(20)^(40)Ca) = 39.962591 u`
`m(""_(20)^(41)Ca) = 40.962278 u`
`m(""_(13)^(26)Al) = 25.986895 u`
`m (""_(13)^(27)Al) = 26.981541 u`.

Text Solution

Verified by Experts

Neutron separation energy `S_(n)` of a nucleus `""_(Z)^(A)X` is
`S(n)=[m_(N)(""_(Z)^(A-1)X)+m(n)-m_(N)(""_(Z)^(A)X)]c^(2)`
From given data, `S(n)(""_(20)^(51)Ca)=8.36MeV, S(n)(""_(13)^(27)Al)=13.06MeV`
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