Consider the fission of `""_(92)^(238)U` by fast neutrons. In one fission event, no neutrons are emitted and the final end products, after the beta decay of the primary fragments, are `""_(58)^(140)Ce` and `""_(44)^(99)Ru`. Calculate Q for this fission process. The relevant atomic and particle masses are
`m(""_(92)^(238)U) =238.05079 u`
`m( ""_(58)^(140)Ce ) =139.90543 u`
`m(""_(44)^(99)Ru ) = 98.90594 u`

Explanation

`Q=[m(""_(92)^(228)U)+m(n)-m(""_(58)^(140)Ce)-m(""_(44)^(99)Ru)]c^(2)=231.1MeV`