The straight line `x+y-1=0` meets the circle . `x^2 +y^2-6x-8y=0` at A and B. Then, the equation of : the circle of which AB is a diameter, is

The straight line x+y - 1= 0 cuts the circle x^(2) + y^(2) - 6x - 8y = 0 at A and B. Find the equation of the circle of which AB is a diameter.

If x-y+1=0 meets the circle. x^(2)+y^(2)+y-1=0 at A and B , then the equation of the circle with A B as diameter is

If x - y + 1 = 0 meets the circle x^(2) + y^(2) + y - 1 = 0 at A and B , then the equation of the circle with AB as diameter is

The line 2x -y +6= 0 meets the circle x^2+y^2 -2y-9 =0 at A and B. Find the equation of the circle on AB as diameter.

If line y= 2x meets circle x^(2) + y^(2) - 4x = 0 in point A and B , then equation of circle of which AB is diameter is

If line y = 4x meets circle x^(2) + y^(2) - 17 x = 0 in points A and B , then equation of circle of which AB is a diameter is

The line 2x-y+6=0 meets the circle x^(2)+y^(2)-2y-9=0 at A and B. Find the equation of the circle on AB as diameter.

If x-y+1=0 meets thwe cicle x^(2)+y^(2)+y-1=0 at a and b, then the equation of the circle with ab as diameter, is