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Let bar(u),bar(v) and bar(w) be 3 vector...

Let `bar(u),bar(v)` and `bar(w)` be 3 vectors such that `|bar(u)|=1`,`|bar(v)|=2`,`|bar(w)|=3` .If the projection of, `bar(v)` along `bar(u)` is equal to that of `bar(w)` along `bar(u),bar(v)` and `bar(w)` are perpendicular to each other, then `|bar(u)-bar(v)+bar(w)|=`

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