Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth. If the ratio of densities of earth and moon is 5/3, then radius of moon in terms of radius of earth will be

Acceleration due to gravity of earth

Acceleration due to gravity on moon is 1//6 of the acceleration due to gravity on earth. If the ratio of densities of earth (rho_(e)) and moon (rho_(m)) is ((rho_(e))/(rho_(m)))=5/3 then radius of moon (R_(m)) in terms of R_(e) will be

The acceleration due to gravity near the surface of moon is-

The acceleration due to gravity on the moon is (1)/(6) th the acceleration due to gravity on the surface of the earth. If the length of a second's pendulum is 1 m on the surface of the earth, then its length on the surface of the moon will be

If g_(e) is acceleration due to gravity on earth and g_(m) is acceleration due to gravity on moon, then

The acceleration due to gravity on the surface of the moon = (1)/(6) the acceleration due to gravity on the surface of the earth. What will be the mass of a steel ball on the surface of the moon, if its mass on the surface of the earth is 6 kg ?

The height at which the acceleration due to gravity becomes (g)/(9) (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth is

If R is the radius of the earth and g the acceleration due to gravity on the earth’s surface, the mean density of the earth is