The ratio of the area of the incircle to the area of `Delta ABC` is

Ratio of area of the incircle to the area of triangle ABC

In a triangle ABC, prove that the ratio of the area of the incircle to that of the triangle is pi:cot((A)/(2))cot((B)/(2))cot((C)/(2))

In a triangle ABC, prove that the ratio of the area of the incircle to that of the triangle is pi:cot(A/2) cot(B/2) cot(C/2)

ABC is a triangle with base AB. D is a point on AB such that AB = 5 and DB = 3. What is the ratio of the area of Delta ADC to the area of Delta ABC ?

ABC is a triangle with base AB. D is a point on AB such that AB = 5 and DB = 3. What is the ratio of the area of Delta ADC to the area of DeltaABC ?

The ratio of the areas of the incircle and the circumcircle of a square is-

The ratio of the areas of the incircle and the circumcircle of a square is-

The ratio of the area of the incircle and the circum-circle of a square is

Delta ABC ~ Delta QRP . If the ratio of the area of Delta ABC to the area of Delta PQR is 576 : 169. AB =10 cm, AC = 12 cm and BC =13 cm. then the length of PR (in cm) is equal to: